00:02
In this question, we can write down the heat generated in the electrical wire due to the result of a resistance as e, which is equal to v, multiplied by i, where e is the heat generated, v is the potential drop through the wire, and i is the current through the wire.
00:19
We also have the value of v, which is equal to 60 watt, then the current i, which is equals to 1 .5 ampere.
00:28
Therefore, we can write the generated heat a, e, which is equal to 60 multiplied by 1 .5.
00:37
So ultimately it becomes 90 watt.
00:41
This is the heat generated.
00:46
Heat generated.
00:49
Now, the heat dissipated by the convection around the surrounding, we can write q, which is equals to h .a .d.
00:59
So h is the conventional heat transfer coefficient, then t dt is the change in the temperature.
01:08
And this a is the surface area.
01:12
Now we also have all this values here.
01:15
The diameter of this wire, which is 0 .003 meter.
01:20
And the length of the wire is 2 meter...