Given that $\mu = 3.9$ BM, we can solve for n:
$3.9 = \sqrt{n(n+2)}$
$3.9^2 = n(n+2)$
$15.21 = n^2 + 2n$
$n^2 + 2n - 15.21 = 0$
Solving this quadratic equation using the quadratic formula:
$n = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$
where a = 1, b = 2, and c =
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