4 a simple coffee cup calorimeter is often used to determine...

A simple coffee-cup calorimeter is often used to determine the amount of heat released when an acid is neutralized by a base. When 90.0 g of 3.00 M hydrochloric acid (HCl) is neutralized with 90.0 g of 3.00 M sodium hydroxide (NaOH), the temperature of the solution increases from 22.0 °C to 42.0 °C. Using a specific heat capacity of the mixture of 4.2 J/g·°C, how much heat in kJ is released in this reaction, assuming the calorimeter does not absorb any heat and that there is no heat exchange between the calorimeter and the surrounding air. 7.6 kJ 15.1 kJ 22.7 kJ 31.7 kJ 5. If a 4.0 kg block of lead (specific heat capacity = 0.130 J/g·°C) at 100 °C is placed on top of a 6.0 kg block of lead at 300 °C, what will be the final temperature of both blocks, assuming no heat is lost to the surroundings? 180 °C 220 °C 250 °C 150 °C

Transcript

00:01 Hello students in the question we have a neutralization reaction they have given in the reaction so the reaction between n -a -o -h and h -cl so as it is a neutralization reaction we'll get nacl and h2 s products which is salt and butter products we will get in neutralization reaction so they gave 90 grams of n -a -o -h reacts with 90 grams of acl.

00:31 So they gave only this much weights.

00:35 So according to law of mass conservation, we should know that after completion of the reaction, we will get the product as much as a reactant's weight.

00:45 So we'll get here 90 grams of nacl and also 90 grams of water.

00:51 So we know the mass of the water.

00:54 So m is equal to 90 grams.

00:57 And in the question, we have.

00:59 Temperature initially when the reaction is started t1 is equal to 22 degrees celsius and the final temperature is t2 is equal to 42 degrees celsius so what is is delta t is equal to t 2 minus t 1 that is equal to 42 minus 22 that is equal to 20 degrees celsius we have delta t and also we have specific heat for water specific heat c is equal to 4 .2 joules per gram given in the reaction so you know this much of information by the question so we should calculate the heat released so heat released so heat during this reaction.

02:05 So we should calculate the heat released q is equal to mc delta t, you know this formula.

02:13 So we should write here 4 .2.

02:17 This is 4 .2.

02:19 So m is 90 grams and into means multiplied 4 .2 multiplied by temperature 20 degrees so the answer will be 7 .6 kilojoules per mole nearly so the heat released during this reaction is q is equal to 7 .6 kilojoules okay 7 .6 kilojoues per mole is the heat released during this reaction and there is another part in this question.

03:07 So they gave that there are two blocks, lead blocks, lead blocks are given.

03:16 So these two blocks, first one is weight m1 is equal to 4kz and its temperature t1 is equal to 100 degrees celsius.

03:29 And another one, they have given that m2, block 2 is 6kc weight and also t2 is equal to 300 degrees celsius.

03:43 So these two are getting to contact...

Question

Please give Ace some feedback