4. A solution was made by dissolving. \( 800.0 \mathrm{~g} \) of \( \mathrm{NaOH} \) into \( 2.00 \mathrm{~L} \) of water. Calculate the: (You will need the density of water: \( \mathrm{D}=1 \mathrm{~kg} / \mathrm{L} \) or \( \mathrm{D}=1 \mathrm{~g} / \mathrm{mL} \) ) a. Molality b. Mole fraction c. Mass of of \( \mathrm{NaOH} \)
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- Volume of water = 2.00 L. Density = 1.00 kg/L → mass of water = 2.00 L × 1.00 kg/L = 2.00 kg = 2000 g. Show more…
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