0 g of aluminum (Al).
Given:
- Mass of aluminum (Al) = 50.0 g
- Molar mass of aluminum (Al) = 27.0 g/mol
- Molar mass of aluminum oxide (Al2O3) = 102.0 g/mol
Calculate the moles of aluminum (Al):
\[
\text{Moles of Al} = \frac{50.0 \text{ g}}{27.0 \text{ g/mol}} =
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