4. An object rotates according to the equation $\theta(t) = A + Bt^2 + Ct^3$ where A = 2 rad/s$^2$, B = 3 rad/s$^2$ and C = 5 rad/s. what is the angular velocity of the object at t = 5 s? (a) 540 rad/s (b) 450 rad/s (c) 504 rad/s (d) 405 rad/s $\theta(5) = 2 + 3t^2 + ct^3$
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Given $\theta(t) = A + Bt^2 + Ct^3$, where A = 2 rad/s², B = 3 rad/s², and C = 5 rad/s, we find the derivative: $\omega(t) = \frac{d\theta}{dt} = 2Bt + 3Ct^2$ Show more…
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