Question

(b) 1 - frac{4}{1!} + frac{4^2}{2!} - frac{4^3}{3!} + cdots = sum_{n=0}^{infty} frac{(-1)^n 4^n}{n!}

Name: (b) 1 - frac41! + frac4^22! - frac4^33! + cdots = sumn=0^infty frac(-1)^n 4^nn!
Uploaded: 2022-06-16T08:25:49-08:00
Duration: 1 min 48 s
Channel: Sri K
Description: (b) 1 - frac41! + frac4^22! - frac4^33! + cdots = sumn=0^infty frac(-1)^n 4^nn!

          (b) 1 - frac{4}{1!} + frac{4^2}{2!} - frac{4^3}{3!} + cdots = sum_{n=0}^{infty} frac{(-1)^n 4^n}{n!}

$(b) 1 - frac41! + frac4^22! - frac4^33! + cdots = sumn=0^infty frac(-1)^n 4^nn!$

Added by Jesse M.

Geometry A Common Core Curriculum

Ron Larson, Laurie Boswell 1st Edition

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Solved by Expert Sri K

06/16/2022

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(b) 1 - 4/1! + 4^2/2! - 4^3/3! + ... = sum_{n=0}^{infinity} (-1)^n 4^n / n!

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Question

(b) 1 - frac{4}{1!} + frac{4^2}{2!} - frac{4^3}{3!} + cdots = sum_{n=0}^{infty} frac{(-1)^n 4^n}{n!}

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