00:01
Hello students, they are given by a question in which the concentration of ammonia is 0 .0075 and the ca is 5 .70 into 10.
00:09
We have to find the px, p .o .h, s2 plus concentration and ox minus concentration.
00:15
So, firstly, we have to find the kb and it's formalized that kb is equal to 10x4 minus 14 divided by ka.
00:22
So now we have to put the values here to find the kb.
00:26
So that is 10x4 minus 14 divided by ka is 5 .4 .5.
00:30
0 .70 into 10 rich to the power minus 10.
00:33
And when we calculate it, it is equal to here we have 10x power minus 14 plus 10 divided by 5 .70 and that is equal to trench power minus 4 divided by 5 .70 that is kb of the ammonia.
00:53
Now we have to find the concentration of svo plus.
00:59
So the concentration of scrio plus is equal to 10 to the power minus 14 divided by concentration of oh minus.
01:09
So the concentration of oh minus is equal to c alpha and that is c into alpha is equal to root kb by c.
01:21
So now we have to put the values here.
01:24
So here the concentration c is 0 .075 into under root kb by c.
01:31
Kb by c.
01:31
Kb.
01:32
Is equals to tandrisu the power minus 4 divided by 5 .70 and c is 0 .075.
01:41
And when we calculated the concentration of oh minus ion will be equals to here 0 .00147 molar...