00:02
This question discusses proving the parameters for uniform distribution.
00:09
Now we know that a uniform distribution has all of the values given by 1 over b minus a.
00:21
Now we want to find a mu.
00:27
And in general, when you want to find mu, we can actually take the expectation of some value here, which we're going to call x.
00:40
And that will allow us to find mew.
00:43
Expected values, an average.
00:46
So here we're actually going to take an integral from a to b of our distribution, which is u, which is given by this value here.
00:58
So this is going to be 1 over b minus a, and this is going to be a function of x, let's say, dx.
01:11
Now this is all a constant, right, because our only variable here is x.
01:15
So this just becomes x squared over 2 times our 1 over b minus a here in front...