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4. For the system in Figure, the following data are applicable: p1=7 bars, Q=0.002 m³/s pipe: L (total)=15 m and ID=38 mm oil: SG=0.90 and v=0.0001 m²/s Solve for p2 in units of bars. (40P) VALVE OR FITTING GLOBE VALVE: WIDE OPEN K FACTOR 10.0 1/2 OPEN 12.5 GATE VALVE: WIDE OPEN 0.19 3/4 OPEN 0.90 1/2 OPEN 4.5 1/4 OPEN 24.0 RETURN BEND 2.2 STANDARD TEE 1.8 STANDARD ELBOW? 0.9 45° ELBOW 0.42 90° ELBOW 0.75 BALL CHECK VALVE 4.0 P1 90° ELBOW 90° ELBOW GLOBE VALVE (WIDE OPEN) P2 LOAD FORCE 

          4. For the system in Figure, the
following data are applicable:
p1=7 bars, Q=0.002 m³/s
pipe: L (total)=15 m and ID=38 mm
oil: SG=0.90 and v=0.0001 m²/s
Solve for p2 in units of bars. (40P)
VALVE OR FITTING
GLOBE VALVE: WIDE OPEN
K FACTOR
10.0
1/2 OPEN
12.5
GATE VALVE: WIDE OPEN
0.19
3/4 OPEN
0.90
1/2 OPEN
4.5
1/4 OPEN
24.0
RETURN BEND
2.2
STANDARD TEE
1.8
STANDARD ELBOW?
0.9
45° ELBOW
0.42
90° ELBOW
0.75
BALL CHECK VALVE
4.0
P1
90° ELBOW
90° ELBOW
GLOBE VALVE
(WIDE OPEN)
P2
LOAD FORCE
Show more…
4. For the system in Figure, the following data are applicable: p1=7 bars, Q=0.002 m³/s pipe: L (total)=15 m and ID=38 mm oil: SG=0.90 and v=0.0001 m²/s Solve for p2 in units of bars. (40P) VALVE OR FITTING GLOBE VALVE: WIDE OPEN K FACTOR 10.0 1/2 OPEN 12.5 GATE VALVE: WIDE OPEN 0.19 3/4 OPEN 0.90 1/2 OPEN 4.5 1/4 OPEN 24.0 RETURN BEND 2.2 STANDARD TEE 1.8 STANDARD ELBOW? 0.9 45° ELBOW 0.42 90° ELBOW 0.75 BALL CHECK VALVE 4.0 P1 90° ELBOW 90° ELBOW GLOBE VALVE (WIDE OPEN) P2 LOAD FORCE

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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For the system in Figure, the following data are applicable: P1 = 7 bars Q = 0.002 m^3/s pipe: L (total) = 15 m and ID = 38 mm oil: SG = 0.90 and v = 0.0001 m^2/s Solve for p2 in units of bars. VALVE OR FITTING K FACTOR GLOBE VALVE: WIDE OPEN 1/2 OPEN GATE VALVE: WIDE OPEN 3/4 OPEN 1/2 OPEN 1/4 OPEN RETURN BEND STANDARD TEE STANDARD ELBOW 45 ELBOW 90 ELBOW BALL CHECK VALVE 10.0 12.5 0.19 0.90 4.5 24.0 2.2 1.8 0.9 0.42 0.75 4.0
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Transcript

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00:01 Hello students in this question given as a length of the pipe is 100 meter and their diameter is given as 50 mm density of water is 1000 kilogram per meter cube and pumping pressure is given p into 10 to the power 5 pascal.
00:32 This ct constant is given as 0 .006 and the value of g is 9 .81 meter per second square and the height that 2 minus z 1 is equal to 20 meter in this question.
00:54 We know that the tank a and b are open to atmosphere then by using the bernoulli's theorem pressure at point b will be equal to the z 2 minus z 1 n plus hp n equation number 1 where n is equal to rho into g 2 is 1000 into 9 .81.
01:30 So this is equal to 9810 newton per meter.
01:37 Now, we will consider the point a is as reference term...
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