4. How many combinations without repetition are possible if n = 7 and r = 2? 28 14 21 49
Added by Julia J.
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In this case, n = 7 and r = 2. Plugging in the values into the formula: C(7, 2) = 7! / (2!(7-2)!) = 7! / (2!5!) = (7 * 6 * 5!) / (2! * 5!) = (7 * 6) / 2! = 42 / 2 = 21 Show more…
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