4. (Pre-lab problem) Calculate the equivalent resistance,...

Name: 4. (Pre-lab problem) Calculate the equivalent resistance, the total current, the current through each resistor and the voltage across each resistor. Show calculations then put the results in the table. Check the calculations by analyzing power in the circuit. R1 47 ? R2 1.0 k? R3 510 ? R4 100 ? Vbat 1.5 V R (?) V (V) I (mA) P (W) R1 R2 R3 R4 Req
Uploaded: 2022-05-27T05:29:44-08:00
Duration: 8 min 14 s
Channel: Manoj Rathi
Description: 4. (Pre-lab problem) Calculate the equivalent resistance, the total current, the current through each resistor and the voltage across each resistor. Show calculations then put the results in the table. Check the calculations by analyzing power in the circuit. R1 47 ? R2 1.0 k? R3 510 ? R4 100 ? Vbat 1.5 V R (?) V (V) I (mA) P (W) R1 R2 R3 R4 Req

4. (Pre-lab problem) Calculate the equivalent resistance, the total current, the current through each resistor and the voltage across each resistor. Show calculations then put the results in the table. Check the calculations by analyzing power in the circuit. R1 47 ? R2 1.0 k? R3 510 ? R4 100 ? Vbat 1.5 V R (?) V (V) I (mA) P (W) R1 R2 R3 R4 Req

Transcript

00:01 This question, calculate the equivalent resistance, the total current current to each resistor and the voltage across each resistor.

00:06 Okay.

00:07 So first, let's find out the equivalent resistance.

00:09 So these two are in cs, of course, r1 and r2 are in cs.

00:13 So the equivalent resistance is just going to be the sum of both.

00:18 So that's 47 plus r2.

00:21 That is 1 ,000 kilo -ooms.

00:22 So that is 1047 oms.

00:25 And likewise, r3 and r4 are in cs as well.

00:30 So r3 plus r4 is going to be 510 plus 100 oms.

00:34 That is going to be 610 oms.

00:38 And then these two guys will be in parallel, right? so these two are the resistance and they are in parallel.

00:45 So it's 1047 oms.

00:48 And this is 610 oms.

00:51 And they're equivalent in the case of being in parallel.

00:54 That's going to be our equivalent as r1, r2 over r1 plus r2.

00:59 So what is r1 r2? that's 1047.

01:04 What is r2? that is 610 over 1047 plus 610.

01:10 So this value comes out as 1047 times 610 over 1047 plus 610.

01:21 So that is coming as 385 .4 .4 oms.

01:27 So that is the value of the.

01:30 Resistor are okay and now if we want to find the current through the complete circuit that is just going to be the net voltage v over resistance r so the voltage v is 1 .5 so this is 1 .5 over the value of the resistance which is 385 .4 so this value comes out as a 1 .5 over this value so this is coming as 0 .00389 ampere so this is the net current through the through what you call it as the through the circuit and in milli -amper if you want to write then that's going to be 3 .89 millie ampere okay now if you want to fill up this table then the individual resistances we know so we can just fill that up r1 is 47 r2 is 1000 because that is in kilo -oam r -3 is 510 r4 is 100 and our equivalent is 385 .44 then the voltage drop across then let's first find out the current right so uh now if you want to find out the individual current so this circuit is going to help us so there are two branches and two current uh two branches of resistor which is like this one zero four seven om and six one zero oom and this is at three point eight nine midi ampere so this current is i1 this current is i two so the value of i one from here comes out as i times r2 over r1 plus r2 r2 r2 means this other one and r1 means this so that is a formula so i is 3 .89 r2 is 610 over r1 plus r2 which is 1 1047 plus 600 and 1047 plus 610 610 over this value times 3 .89.

03:39 So this value is coming as 1 .43 ampere.

03:45 That is the value of i1...

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