4. public static void main (String[] args) { try (FileInputStream fis = new FileInputStream ("test.dat");) { // any code written } catch (IOException ex) { System.out.Println("Something goes wrong"); } catch (FileNotFoundException ex) { System.out.Println("Can't find the file"); } } Hint: the above code will not run successfully, why? By using eclipse program find Answer:

          4. public static void main (String[] args) {
try (FileInputStream fis = new FileInputStream ("test.dat");)
{
// any code written
}
catch (IOException ex) {
System.out.Println("Something goes wrong");
}
catch (FileNotFoundException ex) {
System.out.Println("Can't find the file");
}
}
Hint: the above code will not run successfully, why?
By using eclipse program find Answer:

4. public static void main (String[] args)
try (FileInputStream fis = new FileInputStream ("test.dat");)

// any code written

catch (IOException ex)
System.out.Println("Something goes wrong");

catch (FileNotFoundException ex)
System.out.Println("Can't find the file");

Hint: the above code will not run successfully, why?
By using eclipse program find Answer:

Added by Jody C.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Rabeya Zahid

Step 1

The main method is the entry point of the program. Show more…

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```java public static void main(String[] args) { try (FileInputStream fis = new FileInputStream("test.dat")) { // any code written } catch (IOException ex) { System.out.println("Something goes wrong"); } catch (FileNotFoundException ex) { System.out.println("Can't find the file"); } } ```