00:01
Let us see the equation, so we have v0 is equal to 160 multiplied by 3 .3k divided by 3 .3k plus 4 .7k which is equal to 66 volt.
00:14
So for part a, answer would be v0 is equal to 66 volt.
00:20
Then for the part b, we have i is equal to 160 divided by 4 .7k plus 3 .3k which is equal to 20 milliampere.
00:32
So now, pr1 is equal to i square r1, so that is 20 multiplied by 10 raised to power minus 3 whole square multiplied by 4 .7k is equal to 1 .88 w.
00:44
So pr1 would be equal to 1 .88 w and similarly we can find the value for pr2, so that is i square r2.
00:54
So 20 multiplied by 10 raised to power minus 3 whole square multiplied by 3 .3k.
01:00
So pr2 that is power at resistance 2 would be 1 .32 w.
01:05
That is the answer for b part of the equation.
01:07
Now for the c part, we have ir1 is equal to 160 minus 66 divided by r1 is equal to 94 divided by r1...