00:02
In this given problem, we have to find out what is the formula for the compound and consider that the conclusion for the esr spectrum is and also draw the a and b nmr data structure.
00:22
So for this question, the answer is in step first, finding the empirical formula.
00:53
Co is equal to 34 .47 over 58 .9.
01:05
That is equal to 0 .58 over 0 .58 is equal to 1.
01:16
Carbon is equal to 28 .10 over 12.
01:24
2 .34 over 0 .58 is equal to 4 .58 is equal to 4.
01:34
Now for oxygen is equal to 37 .43 over 16 that is equals to 2 .88 over 0 .58 that is equal to 5.
01:54
So the empirical formula is the empirical formula is c0, sorry c0 c405.
02:23
This is the empirical formula formula is c o c o 4 sorry c o c o c o and the structure is c o s c o c o and double bond o this is the structure here c2 so c2 plus so c2 v c2 plus two sigma v this is point group now 13 carbon and mr of this structure we will get to signals the number one signal for the two carbons that are in chain of oxygen second signal will be, will be due to the co carbon.
06:22
Now, if we dissolve it in organic a convert into the structure is co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co, co4, double bone, o...