4) What is the molarity of a hydrochloric acid solution prepared by diluting 200.0 mL of 0.500 M HCl to a total volume of 1.00 L?
Added by Alejandro E.
Step 1
Given: Initial molarity (M1) = 0.500 M Initial volume (V1) = 200.0 mL = 0.200 L Use the formula: \[ \text{moles} = \text{Molarity} \times \text{Volume} \] \[ \text{moles} = 0.500 \, \text{M} \times 0.200 \, \text{L} \] ** Show more…
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