00:01
This problem uses kerchhoff's voltage law.
00:03
Kerchhoff's voltage law says that the sum of the voltages as you work away around a circuit is equal to zero.
00:11
And so we're just going to move around in a clockwise direction starting in the bottom left corner and using the signs on those particular elements.
00:21
And if power is being absorbed by an element like those resistors, then that'll be positive.
00:27
So i start out with minus 12.
00:29
And i have one kilo -oam times the current, then i have a dependent voltage source, so plus 2 times vx, then plus 2k times the current, and then plus 3k times the current.
00:48
And all those will equal 0.
00:51
And we'll use that to find out with the voltage drop there is a v0 and vx.
00:58
So if i combine all my like terms, minus 12 plus 3 vx plus 4 times the current and that's equal to 0.
01:10
Now we know over there on the right hand side we know that vx is equal to 2 kilo -ooms times the current...