00:01
Hello students, hope you are doing great.
00:03
In this question we are asked to find out the heat released.
00:06
So the first reaction that we are given is 2 mol of aluminium reacts with cr2o3 to give al2o3 plus 2 mol of chromium.
00:16
Now here we will find out number of moles of aluminium which is equals to given mass of aluminium divided by its molar mass.
00:24
So here mass of aluminium is given as 10 gram.
00:28
So we have 10 gram divided by 26 .98 gram per mol.
00:35
Solving this we have number of moles of aluminium is equals to 0 .3706 mol.
00:41
Now we will find out number of moles of cr2o3.
00:45
So number of moles of cr2o3 is equals to again its mass that is 25 gram divided by molar mass that is 151 .99 gram per mol.
00:55
Solving this we have number of moles of cr2o3 is equals to 0 .1645 mol.
01:02
So now here we can see the number of moles of cr2o3 is less than number of moles of aluminium.
01:07
So this is the limiting reagent.
01:09
Now we have to find out heat released...