00:01
Hello everyone, let's start the question.
00:03
In this question, we are asked to calculate the ph of a solution which will result from the given set of mixture, which in the first part is for a mixture of 50 milliliters volume of 0 .15 molar h -ch -o -2 with 75 milliliters of 0 .13 molar nach -o2.
00:28
So now in order to calculate the ph, first let us write the total volume, total volume of the mixture, total volume of mixture which will be equal to the sum of 50 milliliters which is for h -c -h -o -2 added to 75 milliliter which is the volume for our second compound and it will give us a sum total of 125.
01:02
Milliliter.
01:04
This is our total volume.
01:06
So now we will be calculating the concentration of both the given compounds by using the dilution formula using dilution formula.
01:23
For which we can write the expression as c that is the concentration of the stock solution multiplied by the volume denoted by v for the given stock solution is equal to the product of concentration and volume for the dilute solution.
01:53
Now see here denotes the concentration and capital v stands for the volume.
02:03
So now therefore we can write it in this manner.
02:06
That the concentration of the dilute solution, that is, the concentration of h -cho -2, will be equal to the multiplication of stock solution, concentration and volume, which is equal to 0 .15 molar multiplied by 50 milliliter, that is its volume, dividing it by the total volume which is 1 .25 milliliter.
02:43
This on further simplification will come out to be equal to 0 .060 molar.
02:52
This is the concentration...