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4. (10 points) For this problem only, assume that the standard deviation of the number of practice swings per round for all rounds of golf played at the Master's in the past five years is 13.6. What is the minimum number of rounds of golf that would need to be selected for the sample to allow the calculation of a 99% confidence interval with margin of error no larger than 5. Please circle your final answer. 

          4. (10 points) For this problem only, assume that the standard deviation of the number of practice swings per round for all rounds of golf played at the Master's in the past five years is 13.6. What is the minimum number of rounds of golf that would need to be selected for the sample to allow the calculation of a 99% confidence interval with margin of error no larger than 5. Please circle your final answer.
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4. (10 points) For this problem only, assume that the standard deviation of the number of practice swings per round for all rounds of golf played at the Master's in the past five years is 13.6. What is the minimum number of rounds of golf that would need to be selected for the sample to allow the calculation of a 99% confidence interval with margin of error no larger than 5. Please circle your final answer.

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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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4.10 points For this problem, only assume that the standard deviation of the number of practice swings per round for all rounds of golf played at the Masters in the past five years is 13.6. What is the minimum number of rounds of golf that would need to be selected for the sample to allow the calculation of a 99% confidence interval with a margin of error no larger than 5? Please circle your final answer.
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Transcript

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00:02 To make our 95 % confidence interval, we're going to use this formula where x bar is our sample mean of 75.
00:12 So in both parts of this formula here, this first box is 75 and the two, the box after the two, is 75.
00:22 Now, at 95 % confidence, the critical value z is 1 .96.
00:28 So we're going to plug in a 1 .96 into each of those boxes.
00:34 And then our fraction is the population standard deviation over the square root of our sample size.
00:42 So our population standard deviation is 6 .85.
00:48 That's going to be both of our numerators.
00:52 And then our denominator is the sample size of 36.
00:57 So this would be the square root of 36...
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