Question

4.16. In the circuit depicted in Fig. 4.57, $I_{S1}$ = $2I_{S2} = 4 \times 10^{-16}$ A. If $\beta_1 = \beta_2 = 100$ and $R_1 = 5 k\Omega$, compute $V_B$ such that $I_X = 1 mA$.

Name: 416 in the circuit depicted in fig 457 is1 2is2 4 times 10 16 a if beta1 beta2 100 and r1 5 komega compute vb such that ix 1 ma 13026
Uploaded: 2024-05-15T12:43:47-08:00
Duration: 2 min 32 s
Channel: Adi S
Description: 416 in the circuit depicted in fig 457 is1 2is2 4 times 10 16 a if beta1 beta2 100 and r1 5 komega compute vb such that ix 1 ma 13026

          4.16. In the circuit depicted in Fig. 4.57, $I_{S1}$ =
$2I_{S2} = 4 \times 10^{-16}$ A. If $\beta_1 = \beta_2 = 100$ and
$R_1 = 5 k\Omega$, compute $V_B$ such that $I_X = 1 mA$.

Added by Christine P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

05/15/2024

Step 1

Since $\beta_1 = \beta_2 = 100$, we can assume that the transistors are in active mode. The current $I_X$ flows through the base of $Q_1$. The base current of $Q_1$ is $I_{B1} = I_X / \beta_1 = 1 mA / 100 = 10 \mu A$. The emitter current of $Q_1$ is $I_{E1} = Show more…

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4.16. In the circuit depicted in Fig. 4.57, $I_{S1}$ = $2I_{S2} = 4 \times 10^{-16}$ A. If $\beta_1 = \beta_2 = 100$ and $R_1 = 5 k\Omega$, compute $V_B$ such that $I_X = 1 mA$.