4.20. Find the inverse $z$-transform of \begin{equation} X(z) = \frac{z}{z(z-1)(z-2)^2}, \quad |z| > 2 \end{equation}
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x(z) = z / (z(z-1)(z-2)^2) x(z) = A/z + B/(z-1) + C/(z-2) + D/(z-2)^2 Multiplying both sides by z(z-1)(z-2)^2, we get: z = A(z-1)(z-2)^2 + Bz(z-2)^2 + Cz(z-1)(z-2) + Dz(z-1) Now, we can solve for A, B, C, and D by substituting z = 0, 1, 2, and infinity. Show more…
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