Question

4.34. Consider the Minitab output below. ONE-SAMPLE Z Test of mu = 30 vs not = 30 The assumed standard deviation = 1.3 N Mean SE Mean 95% CI Z P 15 31.400 0.336 (30.742, 32.058) ? ? a. Fill in the missing values. What conclusions would you draw? b. Is this a one-sided or two-sided test? c. Use the output and a normal table to find a 95% CI on the mean. d. How was the SE mean calculated? e. What is the P-value if the alternative hypothesis is H? : ? > 30?

          4.34. Consider the Minitab output below.
ONE-SAMPLE Z
Test of mu = 30 vs not = 30
The assumed standard deviation = 1.3
N Mean SE Mean 95% CI Z P
15 31.400 0.336 (30.742, 32.058) ? ?
a. Fill in the missing values. What conclusions would you draw?
b. Is this a one-sided or two-sided test?
c. Use the output and a normal table to find a 95% CI on the mean.
d. How was the SE mean calculated?
e. What is the P-value if the alternative hypothesis is H? : ? > 30?

4.34. Consider the Minitab output below.
ONE-SAMPLE Z
Test of mu = 30 vs not = 30
The assumed standard deviation = 1.3
N Mean SE Mean 95% CI Z P
15 31.400 0.336 (30.742, 32.058) ? ?
a. Fill in the missing values. What conclusions would you draw?
b. Is this a one-sided or two-sided test?
c. Use the output and a normal table to find a 95% CI on the mean.
d. How was the SE mean calculated?
e. What is the P-value if the alternative hypothesis is H? : ? > 30?

Added by Leah J.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Kari Hasz

02/03/2024

Step 1

The missing values are already filled in the output. The sample size (N) is 15, the sample mean is 31.4, and the standard error of the mean (SE Mean) is 0.336. The 95% confidence interval is (30.742, 32.058). Since the entire confidence interval is above 30, we Show more…

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