00:01
Students, welcome here in this question.
00:02
We have a cobalt 60.
00:05
So co 60 is given.
00:08
So is a radius radioactive atoreso tube used to treat cancer.
00:13
So here they are given.
00:15
Energy is given as 2 .2 m .e .b.
00:20
And here 1 m .e .v is equal to 10 .6 electron volts.
00:28
Okay.
00:29
And here 1 electron is equal to 1 .6 multiplied by 10 power minus 19 joules.
00:40
So here, energy is equal to 2 point, so totally, 20 multiplied by 1 .6 multiplied by 10 power minus 19.
00:52
So then it is equal to 3 .52 multiplied by 10 over minus 19.
00:58
Jals, this one, sorry, this one is multiplied by 10 power 10.
01:01
4 6 also there know so this is equal to time powers 13 joules now this one is equal to so we have other things energy is equal to h multiplied by frequency we know that so from this we had to calculate the wavelength of the compound so this one so wavelength of the gamma race we had to calculate so wavelength we had to calculate for gamma rays that are emitting from this cobalt 60 radioactive element.
01:39
So this one is h new...