00:01
Hi, in this question we have a piston assembly which contains 3kg of air at temperature t1 which is given as 20 degrees celsius which we can convert in kelvin as 293 .15 kelvin and the pressure p is given as 300 kilo pascal.
00:29
So now they are telling us that now this assembly is heated at the constant pressure p to temperature t2 which is given as 600 kelvin.
00:43
So now in part a we have to calculate the final volume.
00:49
So now for an ideal gas we know that pv is equals to mrt.
00:56
So now here in this question we'll have two states of the assembly.
01:04
So for state one, which is the initial state, we have the value of temperature is t1.
01:15
The value of pressure will be p and we have to calculate the value of v1.
01:21
So using this formula we can calculate v1 equals to m are t1 divided by p.
01:28
So we'll get the value of v1 which is the initial volume equals to m which is given as 3 into 0 .287 which is a constant.
01:40
T1 is given as 293 .15 kelvin and pressure is 300.
01:47
So on solving this we get the value for v1 which is the initial volume as 0 .81413 meter.
01:54
So now we have state 2 where we have temperature t2 pressure was constant so we'll have pressure same p.
02:11
So here we can calculate the volume equals to v2 will be equals to we can write mr t2 divided by p.
02:22
So on putting the values we'll get 3 into 0 .287 multiplied by 600.
02:29
Which is t2 temperature divided by 300.
02:33
So on solving this, we get the value for final volume v2 equals to 1 .722 meter cube...