45 a solution of ca with a concentration of 654 x 10 5 m is alllowed to react with edta to form

Step 1: Identify the components involved in the reaction. We have calcium ions (Ca²⁺) in a solut

45 a solution of ca with a concentration of 654 x 10 5 m is...

Transcript

00:01 In this question equation is given to us and according to that equation this calcium ions in equis forms it reacts with h2 adta to negative again this is also in the equis form and the reaction it addresses calcium c a h2 a d t a now this is also in aqueous form the requirement of this solution or this particular reaction is basically you know requiring 1 .264 mll of 0 .0 .0 .0 molar of this adta to completely react with all of the calcium that is present in the 5ml sample of tap water.

00:48 So what we have to do in this question that we have to determine the concentration or basically the molar concentration of this calcium.

00:56 Now starting the first of all to determine the concentration we need to determine the to calculate the number of moles and so the number of moles of this calcium will be calculating this by calculating the number of moles needed for this edta in this particular titration experiment so the number of moles basically becomes a malarity into volume because malarity equals two number of moles divided by the total volume of the sample so in this case the number of modes that calculating are basically of h2 adta to negative so malarity is given volume is also given to us so malarity is 0 .01 this multiplied by 1 .264 so it becomes basically the 1 .26 multiplied with 10 rays to the power negative of 5 so these are the number of most of adta now according to the reaction also this chemical equation is balanced that for one mole of adta we require one mall of calcium so basically one mole of adta is neutralizing the 1 mole of calcium so if the sample is consuming this much amount of adta it simply means that these are also the number of moles of calcium so the number of calcium becomes 1 .26 multiplied with the 10 raise to the power negative of 5 now from here we can calculate the concentration quite easily and again the concentration equals or the malarity equals number of mows and divided by the volume volume given to us is basically 5 or in the 5 ml of tap water so 1 .26 multiplied with the 10 raise to the power minus 5 fold divided by volume should in should be in the liter so so the volume in liter basically becomes 0 .005 liters...

Question

45 a solution of ca with a concentration of 6.54 x 10-5 m is alllowed to react with EDTA to form a complex

Question

45 a solution of ca with a concentration of 6.54 x 10-5 m is alllowed to react with EDTA to form a complex

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