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Hi there.
00:03
In this question, we are given this balanced equation, and we are told that we are burning 19 .8 grams of the c5h12 of the pentate.
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And we want to know how many grams of carbon dioxide can be produced.
00:20
What is the mass? so question mark grams.
00:25
All right.
00:25
Well, to convert from one substance to another in a chemical equation, we need to use the mole ratio.
00:30
So because this is a mass to mass stoichiometry problem.
00:35
So in order to convert from one substance to the other, we need that mole ratio.
00:40
And the mole ratio is found by using the coefficients in the balanced equation.
00:44
Since nothing is written in front of the pentane, it's understood that it's a one.
00:48
So for every one mole of pentane, we can produce five moles of carbon dioxide.
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However, right now we do not have moles.
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So our first step is going to be to convert from grams of the pentane to moles.
01:03
And we'll that by using the molar mass given to us in the problem.
01:08
Then we can use that 1 to 5 mole ratio to convert to moles of carbon dioxide.
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And then finally we can convert from moles of carbon dioxide to mass by using carbon dioxide's molar mass, which is also given to us in the problem.
01:28
All right.
01:29
So this is our plan.
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It's going to take us three steps to get from our starting point of 19 .8 grams of c5, h12...