Assume that X is normally distributed with a mean of 10 and a standard deviation of 2. Determine the following: a. P(X < 13) b. P(X > 9) c. P(6 < X < 14) d. P(2 < X < 4) e. P(-2 < X < 8)
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The formula for finding the Z-score is: $$ Z = \frac{X - \mu}{\sigma} $$ Where $X$ is the value, $\mu$ is the mean, and $\sigma$ is the standard deviation. Show more…
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