00:01
Hello everyone in this given problem we have given a circuit diagram of given resistance is 3 -oom 1 -o 4 -oom and 4 -oom and 3 -oom and 2 -oom and the am meteors are connected the current defluxion serves downward and upward so at point p at point p we find at point p this is a point p the equation is 1 1 1 1 plus 4 minus v by 3 is equal to v by 3 plus b minus v by 1.
00:53
So the equation is become 3 plus 4 minus v is equal to v plus 3v minus cv 1.
01:02
So 4 plus 3 is 7 minus v1 is equal to v plus 3 v minus 3 v1.
01:15
So we get 7 plus 3 v1 is equal to 5v.
01:23
Note this is not b1 this is v so there will become 3 plus 4 plus 5 is 5 f.
01:35
So this is the equation number 1.
01:38
This is a super node this point is a super node first.
01:48
This is a node 5 and this is a also a super node 5.
01:50
Super note.
01:52
So next the equation is become 4 minus v2 by 2 plus v1 minus v2 by 4 equals to 1.
02:06
Then we become taken the lcm and but we have become 8 minus 2 v2 plus v1 minus v2 equals to 4.
02:20
3 v2 minus v1 is equal to 4.
02:24
This is equation number.
02:26
2.
02:27
Next at super node 1 solving equation second and next equation becomes v minus v1 divided by 1 is equal to v minus v2 divided by 4 plus v1 by 4 then 4 v is equal 4 minus 4 v1 is equal v1 minus v2 plus v1 this is at node q, at node q...