00:01
In this problem we have a cable that has a load that is a parabolic distribution somehow.
00:09
So we have a load that varies parabolically with the horizontal coordinate here.
00:18
And the function is given by this, which is given in the problem.
00:23
We can form the integrals that are described in the book to get the function of y, that describes the cable.
00:35
And we get two constants of integration.
00:37
And we see we get a quartic function here, or a power of four, because we need to integrate this twice.
00:47
So we can find these two constants of integration if we set the origin here at the low point here, and it's also the midpoint because of the symmetry in the problem.
00:59
So we have that, y at 0 is 0 and then at plus or minus xb, which other is yb.
01:15
And we can see that we have symmetry here.
01:18
And as long as this c1 is 0.
01:22
So we know actually from symmetry c1 needs to be 0.
01:25
And we also find the c2 as 0 from these two conditions.
01:31
Now we also have, again, we can figure out that what this value is by looking at the slope at zero...