4. A capacitance transducer consists of two plates of diameter 2 cm each, separated by an air gap of 0.25 mm. Find the displacement sensitivity if the gap between the two plates changes. Given the permittivity of vacuum is $8.85 \times 10^{-12}$ F/m. (10)
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The problem asks us to find the displacement sensitivity of a capacitance transducer. Displacement sensitivity is defined as the change in capacitance per unit change in displacement (or the gap between the plates in this case). Show more…
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A capacitive transducer using five plates. The dimensions of each plate are 25 × 25 mm, and the distance between plates is 0.25 mm. This arrangement is to be used for the measurement of displacement by observing the change in capacitance with distance x. Calculate the sensitivity of the device. Assume that the plates are separated by air. The permittivity of air is 8.85 × 10^–12 F/m.
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A capacitive sensor consists of two parallel plates in air; the plates being (40 mm square and separated by distance of 1 mm) A sheet of dielectric material of thickness (1 mm and (40 mm) square can slide between the plates. The dielectric constant of the material is (9 and that for air may be assumed as (1) Determine the capacitance of the sensor when the sheet has been displaced so that only half of it is between the capacitor plates Knowing that the permittivity of free space (8.85 pF/m).
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