00:01
Here in this problem, this equation is given and given 25 grams of iron react to its 7 .65 grams of o2.
00:10
We have to find out the mass of fe 2 .03 that will be produced.
00:16
So first here we'll find out number of moles of fe given.
00:22
And that will be the mass of fe given here, 25 grams divided by the molar mass of iron, 55 .8.
00:31
845 grams per mole and we get 0 .4477 moles.
00:40
Now we'll find out number of moles of o2 and the mass of o2 given 7 .65 grams and the molar mass of o2 32 grams per mole and we get 0 .2391 moles.
01:00
Now we'll find out how many moles of o2 will be required by 0 .4477 moles of f .e.
01:11
So, 0 .4477 moles fe need 0 .4477 mole fe times conversion factor 3 moles 0 .427 divided by 4 moles fe.
01:32
Because 4 moles of fe require 3 moles of o2.
01:40
And we get 0 .3358 moles o2...