Question

\( 5 / 4 \) \begin{tabular}{|c|c|c|c|c|c|c} \hline 14 & & & & & \\ & 15 & 2 & 3 & 4 & 5 & 6 \\ \hline 1 & 8 & 2.50 & 32.0 & 3 & & \\ 2 & 2 & 5.0 & 33.0 & & & \\ \hline 3 & 3 & 10.0 & 35.0 & & & \\ \hline 4 & 4 & 20.0 & 38.7 & & & \\ \hline \end{tabular} \[ \frac{4 \text { 4nde }}{\text { 4. }} \] \[ \begin{array}{c} 4 \\ 32.0-2.50=29.5 \\ 33.0-5.00=28.0 \\ 350-10.00=25.0 \\ 38.7-20.0=18.7 \end{array} \] 32 2 \[ 29 \cdot 5 \]

          \( 5 / 4 \)
\begin{tabular}{|c|c|c|c|c|c|c}
\hline 14 & & & & & \\
& 15 & 2 & 3 & 4 & 5 & 6 \\
\hline 1 & 8 & 2.50 & 32.0 & 3 & & \\
2 & 2 & 5.0 & 33.0 & & & \\
\hline 3 & 3 & 10.0 & 35.0 & & & \\
\hline 4 & 4 & 20.0 & 38.7 & & & \\
\hline
\end{tabular}
\[
\frac{4 \text { 4nde }}{\text { 4. }}
\]
\[
\begin{array}{c}
4 \\
32.0-2.50=29.5 \\
33.0-5.00=28.0 \\
350-10.00=25.0 \\
38.7-20.0=18.7
\end{array}
\]
32 2
\[
29 \cdot 5
\]

5 / 4

14

15 2 3 4 5 6

1 8 2.50 32.0 3

2 2 5.0 33.0

3 3 10.0 35.0

4 4 20.0 38.7

(4 4nde )/( 4. )

4

32.0-2.50=29.5

33.0-5.00=28.0

350-10.00=25.0

38.7-20.0=18.7

32 2

29 · 5

Added by Michael L.

Student's Solutions Manual for College Algebra

Margaret L. Lial, John Hornsby, David I.… 12th Edition

Chapter 0

Instant Answer

Solved by Expert Robin Corrigan

Step 1

The table has rows and columns with some filled and some empty cells. The first row and the first column seem to be headers or labels for the rows and columns. Show more…

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\( 5 / 4 \) \begin{tabular}{|c|c|c|c|c|c|c} \hline 14 & & & & & \\ & 15 & 2 & 3 & 4 & 5 & 6 \\ \hline 1 & 8 & 2.50 & 32.0 & 3 & & \\ 2 & 2 & 5.0 & 33.0 & & & \\ \hline 3 & 3 & 10.0 & 35.0 & & & \\ \hline 4 & 4 & 20.0 & 38.7 & & & \\ \hline \end{tabular} \[ \frac{4 \text { 4nde }}{\text { 4. }} \] \[ \begin{array}{c} 4 \\ 32.0-2.50=29.5 \\ 33.0-5.00=28.0 \\ 350-10.00=25.0 \\ 38.7-20.0=18.7 \end{array} \] 32 2 \[ 29 \cdot 5 \]