00:01
Hello students in this question, a backhoe and hydraulic cylinders as shown in the figure is been given, whose pre -body diagram is shown on the right -hand side.
00:10
And in this pre -body diagram, let us take this angle as 120 degree, this as 60 degree and this as 45 degree.
00:19
Now for the case of arm a -b, the force acting can be taken as f -a -b, under than for arm a -d, the force can be taken as f -a -b.
00:30
And finally for the arm ac the force can be taken as fac and in this question we are asked to find out the value of force fab force fad and finally force fac and from the figure we can say that the moment about this particular point e can be taken as summation of m e to be equal to a value of zero which according to the free body diagram can be rewritten as facc into course value of 60 degree into 0 .3 plus fac into sine value of 60 degree into 0 .075 minus work done w into 0 .45 to be equal to a value of 0.
01:20
Where in this question, the weight capitalized w is taken to be 6 ,000 newton.
01:26
The above equation, the above equation and undergoing in doing simplification, we get the value of force ac to be equal to 12 .56 kilo -newton.
01:34
Now from the free -body diagram, we can say that the force along y -axis, which is taken as summation of fy, is taken to be a value of 0, which can be simply written as fac into sine 60 degree minus force fab into course 45 degree will be equal to a value of 0...