5. A 15N force is applied to a cord wrapped around a pulley of mass M = 4kg and radius R = 33cm. The pulley accelerates uniformly from rest to an angular speed $omega_f$ = 30 rad/s in 3 seconds. If the frictional torque (at axle) is $ au_f$=1.10mN, determine a) The angular acceleration $alpha = frac{Delta omega}{Delta t}$ b) The moment of Inertia of the pulley (disk I = (1/2) m R^2) c) The linear speed v
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We know the initial angular speed (wi) is 0 rad/s, the final angular speed (wf) is 30 rad/s, and the time (t) is 3 seconds. We can use the formula: wf = wi + alpha * t Rearranging for alpha, we get: alpha = (wf - wi) / t alpha = (30 - 0) / 3 alpha = 10 Show more…
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