5. (a) Set up the partial fraction decomposition of $\frac{6}{x^2(x^2+9)}$. (You do not need to solve for the constants or perform any integration.)
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We can factor the denominator as $x^2(x^2+9)$. The partial fraction decomposition will have the form: $\frac{6}{x^2(x^2+9)} = \frac{A}{x} + \frac{B}{x^2} + \frac{Cx+D}{x^2+9}$ where A, B, C, and D are constants. Show more…
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