5) At t=0, an emf of 500 V is applied to a coil that has an inductance of 4.0 H and a resistance 100 Ohm. The energy stored in the magnetic field of the inductor gradually increases from zero to the value of 32 J reached at a specific instant of time, t. This specific moment of time is calculated to be approximately
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We can use Ohm's law to do this: V = IR Where V is the voltage, I is the current, and R is the resistance. Rearranging the equation, we get: I = V/R Substituting the given values, we have: I = 500 V / 100 Ω = 5 A Show more…
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Ankur S.
(II) At $t = 0,$ the current through a 45.0-mH inductor is 50.0 mA and is increasing at the rate of 115 mA/s. What is the initial energy stored in the inductor, and how long does it take for the energy to increase by a factor of 5.0 from the initial value?
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