Question

5. In a right-handed LC transmission line with L<sub>R</sub>=300 nH/m and C<sub>R</sub>=2000 pF/m, the wave equation would be \begin{align} a) \frac{\partial^2 v(x,t)}{\partial x^2} &= 150 \frac{\partial^2 v(x,t)}{\partial t^2} \\ b) \frac{\partial^2 v(x,t)}{\partial x^2} &= \frac{6}{10^{16}} \frac{\partial^2 v(x,t)}{\partial t^2} \\ c) \frac{\partial^2 v(x,t)}{\partial x^2} &= \frac{10^{16}}{6} \frac{\partial^2 v(x,t)}{\partial t^2} \\ d) \text{none above} \end{align}

          5.
In a right-handed LC transmission line with L<sub>R</sub>=300 nH/m and C<sub>R</sub>=2000 pF/m, the wave
equation would be
\begin{align*}
a) \frac{\partial^2 v(x,t)}{\partial x^2} &= 150 \frac{\partial^2 v(x,t)}{\partial t^2} \\
b) \frac{\partial^2 v(x,t)}{\partial x^2} &= \frac{6}{10^{16}} \frac{\partial^2 v(x,t)}{\partial t^2} \\
c) \frac{\partial^2 v(x,t)}{\partial x^2} &= \frac{10^{16}}{6} \frac{\partial^2 v(x,t)}{\partial t^2} \\
d) \text{none above}
\end{align*}

Show more…

5.
In a right-handed LC transmission line with L<sub>R</sub>=300 nH/m and C<sub>R</sub>=2000 pF/m, the wave
equation would be

a) (∂^2 v(x,t))/(∂ x^2) = 150 (∂^2 v(x,t))/(∂ t^2)

b) (∂^2 v(x,t))/(∂ x^2) = (6)/(10^16)(∂^2 v(x,t))/(∂ t^2)

c) (∂^2 v(x,t))/(∂ x^2) = (10^16)/(6)(∂^2 v(x,t))/(∂ t^2)

d) none above

Added by -Scar R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Emily Anderson

Step 1

Now, let's substitute the given values for the inductance and capacitance per unit length: ∂²v(x,t) / ∂x² = (1/(LR*CR)) ∂²v(x,t) / ∂t² ∂²v(x,t) / ∂x² = (1/(300 nH/m * 2000 pF/m)) ∂²v(x,t) / ∂t² ∂²v(x,t) / ∂x² = (1/(300 * 10^-9 H/m * 2000 * 10^-12 F/m)) Show more…

Show all steps

lock

Thanks for your feedback!

In a right-handed LC transmission line with LR=300 nH/m and CR=2000 pF/m, the wave equation would be: âˆ‚Â²v(x,t) âˆ‚Â²v(x,t) a) : 150 âˆ‚xÂ² âˆ‚tÂ² âˆ‚Â²v(x,t) b) âˆ‚xÂ² 6 âˆ‚Â²v(x,t) 1016 âˆ‚tÂ² âˆ‚Â²v(x,t) âˆ‚xÂ² 1016 âˆ‚Â²v(x,t) 6 âˆ‚tÂ² d) none above

Play audio

Feedback

Powered by NumerAI

Emily Anderson and 73 other subject Physics 102 Electricity and Magnetism educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later