5. Parallel Force Systems Sum the moments about each end of...

5. Parallel Force Systems Sum the moments about each end of the beam to determine the end reactions of the parallel force system shown. Check that the sum of vertical forces is zero. DATASET: 3 -1- -2- Distance A 4 FT Distance B 10 FT Distance C 6 FT Force P1 9 KIPS Force P2 2 KIPS Force w1 0.47 KLF P1 P2 w1 R1 R2 A B C # Question Your Response Correct Answer Score 1 Total force from distributed load: W1 4.7 KIPS 4.7 KIPS 5 2 Distance of total load W1 from left reaction 9 FT 9 FT 5 3 Total applied downward force 15.7 KIPS 15.7 KIPS 5 4 Left End Reaction (R1) KIPS SUBMIT 5 Right End Reaction (R2) KIPS SUBMIT Current Score: 15 / 25

Transcript

00:01 Hi, in this question we need to find the support reactions at the ends of a beam.

00:07 Here there is a simply supported beam.

00:10 This beam is supported at the point 1, that is the left end, the reaction is r1 and at the right end the reaction is r2.

00:21 Now let us determine the total force of the uniformly distributed load acting for a distance of 10 feet.

00:30 The total load of the uniformly distributed load is given by w1 is equal to small w1 multiply with distance b.

00:46 Now let us plug the given values.

00:49 Small w1 is given as 0 .47 klf.

00:57 Multiply with the distance is 10 feet.

01:00 On calculation we obtained the total load of the uniformly distributed load is 4 .7 kips.

01:18 Next we need to determine the distance of the total load, w1, from the left reaction r1.

01:28 This total load, that is, this 4 .7 kips, will be acting at the center of gravity of this loading system.

01:35 The center of gravity of this loading system lies at a distance of the b by 2, that is at this center.

01:46 That means this distance will be 5 feet.

01:56 Therefore, the distance, let us say x1 is equal to a plus b by 2.

02:08 The value of a is 4 feet and the value of b is 10 feet, 10 divided by 2.

02:19 On calculation we obtain the distance of the total load from the left hand support x1 is equal to 9 feet.

02:32 Now coming to the next question.

02:35 The total applied downward force.

02:38 The total applied downward force, w is equal.

02:43 To this is acting in the downward direction and this force is also acting in the downward direction...

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