00:01
The gauge pressure is given to be equal to 12 cm is equal to 12 centimeter of mercury that is hg which is lower than which is lower than the atmospheric pressure than the atmospheric pressure pressure of 76 centimeter of h g hence we can conclude that hence gorge pressure gorge pressure at point a is lower than the atmospheric pressure is lower than the atmospheric pressure.
00:54
This will be the first part of the question.
00:57
Moving forward to the next part, we have this, that we have the pressure gorge in figure 2 reads 12 centimeter mercury.
01:04
The pressure watch reads 12 cm of hhg therefore the pressure exerted by the trapped air on the pressure gorge and hence on the fluids below will be p air which is equal to 12 centimeter hhg which is going to be equal to density of mercury multiplied by gravity multiplied by height so from this we can conclude that we will have this is equal to 13 ,546 kg per meter cube into 9 .8 meter per second square multiplied by 0 .1 to meter.
01:56
This is equal to 15 ,930 pascal.
02:00
Here we can say that according to pascal's law of pressure for confined fluids, this pressure will be exerted.
02:06
The pressure will be exerted equally throughout.
02:16
The fluids throughout the fluids and this is based on the pascal's law pascal's law of pressure for confined fluids for confined fluids here we can say that for height of liquid column a height of liquid column a is going to be 59 30 is equal to density of oil, this pressure we have already calculated.
02:57
So this pressure is equal to density of oil multiplied by the gravity multiplied by height.
03:04
So here we can say that 15930 is equal to, we have density of oil as 800 kg per meter cube, multiplied by gravity is 9 .8 meter per second square...