00:01
Hello students welcome here in this question we have some reactions so the first question first reaction 2 r 3 s 2 bromo 3 methyl hexane is given so this one is reacting with nacn imprints of dmso and 25 degrees celsius so what happens here here now see a necrophiline substitution reaction is taking place.
00:38
So if you see the structure here, br, this one is mixed.
00:51
When it is reacted with this one, sn2 mechanism will happen.
00:56
So cn minus which is present, it will go and attack from backside and it will go outside.
01:03
So nabr will get remand released.
01:06
So here the compound will get br and here it is.
01:14
So this is a product that is produced mainly.
01:20
And the second reaction here is b.
01:26
E 3 methyl hex -3 -in is reacting with hbr.
01:39
What happens here? this is addition reaction.
01:42
So as addition reaction we can see here the structure of this one, e compound, so methyl group.
01:55
So this is the compound e compound.
01:58
So what happens then hbr is produced? hbr is taken.
02:02
So the secondary, both are secondary carbocadian.
02:05
So this is a more stable one.
02:07
So because it is tertiary carbogadian and this one is secondary carbocadian and this one is secondary carbokadian will produce.
02:12
So that's right.
02:13
The compound it is produced here.
02:20
So here it is h and here it is h...