00:01
Hi students, here we have two questions.
00:03
In the first question we have to find out the magnetic force, magnetic force and what is the relation of magnetic force? f is equal to qbb sin theta, qbb sin theta where q is the charge, b is the velocity of this charged particle or speed of the particle and b, b is the magnetic field strength and theta, theta is the angle between b and b, velocity and magnetic field.
00:50
Here q is given as charge of the particle, q is equal to plus 10 micro coulomb or is equal to 10 into 10 raise to minus 6 coulomb and its speed v is equal to 2 .50 into 10 raise to 6 and then enters into a magnetic field of strength, magnetic field strength v is equal to 4 .40 into 10 raise to 5 tesla, velocity is meter per second.
01:29
Now we have to find out the theta.
01:31
Here it is mentioned that velocity is left to the page and magnitude is top to the page.
01:37
So if this is the page here, velocity will be in this direction and magnitude will be in this direction.
01:44
This is velocity and this is magnitude.
01:47
So this magnetic field, so what will be the angle between b and b is 90 degree.
01:55
So theta is 90 degree.
01:57
So substituting the values here, f is equal to q 10 into 10 raise to minus 6 into v 2 .50 into 10 raise to 6 into magnetic field b 4 .40 into 10 raise to 5 into sin 90 degree.
02:22
That's equal to 1 .1 into 10 raise to 7 newton.
02:30
So the magnetic force, therefore magnetic force is 1 .1 into 10 raise to 7 newton.
02:46
Hence the answer.
02:48
Then moving towards the second question.
02:50
So moving towards the second question, it's asked about the magnetic force direction, magnetic force direction.
03:02
So in order to find out the direction of the magnetic force, let it be the paper...