For an exponential distribution with parameter $\lambda = 1$, the expected value is $E[X] = \frac{1}{\lambda} = 1$.
Therefore, $P(X \ge 5) \le \frac{1}{5} = 0.2$.
Since $P(X \ge 5)$ is a probability, it must be between 0 and 1. Thus, the boundaries are $0 \le P(X
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