00:01
Hello student we have given a mean and standard deviation on a standardized test.
00:11
Now for test a mean is equal to 500 and standard deviation is equal to 100.
00:24
For test b mean is equal to 150 and standard deviation is equal to 8 and for test c mean is equals to 70 and standard deviation is equal to 50.
00:40
Now we have to find out a score of 450 on test a corresponding what score on test b.
00:55
So here, that is equal to x minus mu divided by sigma.
01:03
Now we interchange formula as x is equal to th th into sigma plus mu.
01:12
Now we have to find out x the score on test b when score on test a is 450.
01:21
So for test a, th is equals to 450 minus 500 divided by 100.
01:38
So z is equals to minus 0 .5.
01:42
So z is equals to minus 0 .5.
01:46
Now for test b, now for test b, x is equals to here z is equals to minus 0 .5 into sigma, which is equals to 8 plus mu, which is equals to 150.
02:06
Now solving, it will give the value of x, which is equals to 1 .4 .4 .5...