00:02
In the galvanic cells, the half reaction given are cu plus aquas plus electron given c u.
00:14
Similarly, i2 s plus 2 electron giving 2 i minus.
00:24
These are the half reactions.
00:27
The first question asked to determine the cell potential for the spontaneous reaction under standard condition.
00:36
Here in this case, the standard reduction potential of i2 or i minus is more than that of c plus or cu minus.
00:43
Hence, this is the reduction reaction.
00:49
Since its reduction potential is high, so this is the cathode.
00:53
And this is the oxidation reaction and this is the anode.
01:02
So in the first question it is asked to determine the cell potential.
01:06
So the cell potential limit is e -cell.
01:09
Is equal to e cathode minus potential of anode cell potential of anode so here cathode is this one so i 2 bar i minus minus cell potential of cu plus bar c u and cell potential is 0 .5355 minus 0 .52 which gives the standards reduction the standard cell potential as 0 .0155 volt.
01:54
Here since the e -cell is positive, according to the gibbs free energy equation, delta g is equal to minus n of e -cell, the value of delta g becomes negative since the given reaction is positive.
02:09
Therefore it is a spontaneous reaction.
02:13
Now according to the second sub -question, it is asked if the cell in a part is operated at 298 kelvin, with cu plus is equal to 2 .5 molar and i minus is equal to 3 .5 molar...