00:01
Question number 64.
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In this question we have to find the equivalent resistance between points a and b.
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The given network is like this.
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This is 1 ome.
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This is also 1 oom and this is 1 ome.
00:28
Each resistance is of 1 ome.
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And there are 2 more resistances like this.
00:39
It is given that each resistance is of 1 ome.
00:42
And there are 2 more resistances like this.
00:42
1 om so we can see that this 1 om and this 1 om are in series so by series combination formula we can write a combined resistance between these two this combined resistance will be of 2 om because these two resistances were 1 oom 1 om and they were in series so there will be equivalent resistance for both of them which is of 2 oms.
01:22
Now again this 2 oom and this 1 ome are in parallel combination.
01:31
So there combined resistance will be 1 divided by 1 plus 1 by 2.
01:45
This is equal to 0 .67...
