1 pt 5.0-kg object slides down a frictionless surface inclined at an angle of 30Ā° from the horizontal. The total distance moved by the object along the plane is 10 meters. The work done on the object by the normal force the surface is: 0.25 kJ 0.50 kJ 0.58 kJ 0.43 kJ 0 kJ
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Step 1: The work done by a force is given by the equation: $W = Fd\cos(\theta)$ where $W$ is the work done, $F$ is the force, $d$ is the displacement, and $\theta$ is the angle between the force and the displacement. Show moreā¦
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A 5kg object slides down a frictionless surface inclined at an angle 30 degrees from the horizontal. The total distance moved by the object along the plane is 10m. The work done on the object by the force of the gravity is approximately.. a) 0.25 kJ b) zero c) 0.50 kJ d) 0.58 kJ e) 0.43 kJ
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