500g of copper metal is reacted with 2.5 L of 3.0 mol/L nitric acid solution. Calculate how much of the copper metal remains after the reaction is complete. Cu(s) + 4HNO3(aq) -> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)
Added by Cameron P.
Step 1
The molar mass of copper (Cu) is approximately 63.55 g/mol. So, the number of moles of copper is: 500 g / 63.55 g/mol = 7.87 mol The number of moles of nitric acid (HNO3) is: Volume (L) * Concentration (mol/L) = 2.5 L * 3.0 mol/L = 7.5 mol Show more…
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