00:01
Hello, in this question we have ra at this position, this is p at c, d position we have this force and this rb at b, this is 2p right.
00:18
This is l by 4, this is l by 2 and this is l by 4 again.
00:24
So, summation of forces should be 0.
00:27
So, ra plus rb plus p should be equals to 2p.
00:32
So, ra plus rb equals p that is our first equation.
00:37
Summation of all movements should be 0 that is this multiplied by 3l by 4 plus rb multiplied by l equals 0 at a.
00:49
So, from here rb turns out to be 1 .25p and ra turns out to be minus 0 .25p.
00:57
Negative sign indicates that ra is in opposite direction right.
01:02
So, now the diagram becomes like this a 0 .25p, p at c position b we have 1 .25p and we have 2p here right...