Question

5.18. An infinite plane sheet lying in the xy-plane carries current of uniform density $\mathbf{J}_s = -0.1(\cos 2\pi \times 10^6 t \mathbf{a}_x + \cos 4\pi \times 10^6 t \mathbf{a}_y)$ A/m The medium on either side of the sheet is characterized by $\sigma = 10^{-3}$ S/m, $\epsilon = 18\epsilon_0$, and $\mu = \mu_0$. Find E and H on either side of the current sheet.

          5.18. An infinite plane sheet lying in the xy-plane carries current of uniform density
$\mathbf{J}_s = -0.1(\cos 2\pi \times 10^6 t \mathbf{a}_x + \cos 4\pi \times 10^6 t \mathbf{a}_y)$ A/m
The medium on either side of the sheet is characterized by $\sigma = 10^{-3}$ S/m, $\epsilon = 18\epsilon_0$, and
$\mu = \mu_0$. Find E and H on either side of the current sheet.

5.18. An infinite plane sheet lying in the xy-plane carries current of uniform density
𝐉s = -0.1(cos 2π× 10^6 t 𝐚x + cos 4π× 10^6 t 𝐚y) A/m
The medium on either side of the sheet is characterized by σ = 10^-3 S/m, ϵ = 18ϵ0, and
μ = μ0. Find E and H on either side of the current sheet.

Added by Alfonso C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Krishna J

Step 1

The current density vector Js is given by Js = -0.1cos(2π10a) + cos(4π10a) A/m. The direction of the current density vector is perpendicular to the plane of the sheet. Since the sheet lies in the xy-plane, the current density vector is in the z-direction. Show more…

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5.18. An infinite planar sheet lying in the xy-plane carries a current of uniform density Js = -0.1cos(2Ï€10a) + cos(4Ï€10a) A/m. The medium on either side of the sheet is characterized by Ïƒ = 10^-3 S/m, Îµ = 18Îµ0, and Î¼ = Î¼0. Find E and H on either side of the current sheet.